Is any() evaluated lazily?

Question

I am writing a script in which i have to test numbers against a number of conditions. If any of the conditions are met i want to return True an

Answer 1

Yes, and here is an experiment that shows it even more definitively than your timing experiment:

import random

def some(x):
    print(x, end = ', ')
    return random.random() < 0.25

for i in range(5):
    print(any(some(x) for x in range(10)))

typical run:

0, 1, 2, True
0, 1, True
0, True
0, 1, 2, 3, True
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, False