Why isn't my code printing like it should?

Question

I\'m trying to create a for in Clojure.

I\'m following the cheats sheet from the Clojure site.

e.g:

(take 100 (for [x (range 100000000) y (ra         


        

Answer 1

Actually, it is working for me. The last example does print one hundred "Hello World", but the take gets just one hundred nils that are also printed in the REPL. The first example works as it is:

user=> (take 100 (for [x (range 100000000) y (range 1000000) :while (< y x)] [x y])) ([1 0] [2 0] [2 1] [3 0] [3 1] [3 2] [4 0] [4 1] [4 2] [4 3] [5 0] [5 1] [5 2] [5 3] [5 4] [6 0] [6 1] [6 2] [6 3] [6 4] [6 5] [7 0] [7 1] [7 2] [7 3] [7 4] [7 5] [7 6] [8 0] [8 1] [8 2] [8 3] [8 4] [8 5] [8 6] [8 7] [9 0] [9 1] [9 2] [9 3] [9 4] [9 5] [9 6] [9 7] [9 8] [10 0] [10 1] [10 2] [10 3] [10 4] [10 5] [10 6] [10 7] [10 8] [10 9] [11 0] [11 1] [11 2] [11 3] [11 4] [11 5] [11 6] [11 7] [11 8] [11 9] [11 10] [12 0] [12 1] [12 2] [12 3] [12 4] [12 5] [12 6] [12 7] [12 8] [12 9] [12 10] [12 11] [13 0] [13 1] [13 2] [13 3] [13 4] [13 5] [13 6] [13 7] [13 8] [13 9] [13 10] [13 11] [13 12] [14 0] [14 1] [14 2] [14 3] [14 4] [14 5] [14 6] [14 7] [14 8])

For actually printing, you can try a more easy loop:

(dotimes [i 100] (println "Hello World"))

Finally, if you use for, you don't need the :while, as the range already has 100 elements:

(take 100 (for [a (range 100)] 
               (println "Hello World")))