C++ make a variable type depend on user input

Question

I want a function that creates an array for testing purposes:

• The idea es to make the user select the type of elements the array will contain (int, float, doub

Answer 1

it can be done using void* but in that case you need to do type casting yourself (as pointed out by @Rob) i.e. using reinterpret_cast operator or similar. Here is a simple example with void*

 void* vector(){
    int t;
    int op;
    cout << "Size: \n";
    cin >> t;
    cout << "Select type\n";
    cin >> op;
    switch(op) {
     case 0:
           // Create the array with the selected option...
            return  reinterpret_cast(new int[t]);

     case 1:
            // Create the array with the selected option...
            return  reinterpret_cast(new double[t]);

     default:
            // Other stuff;
            return  reinterpret_cast(new float[t]);
       }
    }

Note: you can look at working of malloc() function, it always returns void* to allocated memory and you have to type cast it yourself e.g malloc(sizeof(int)*t)