What is wrong with the short circuit logic in this Java code?

Question

Why doesn\'t func3 get executed in the program below? After func1, func2 doesn\'t need to get evaluated but for func3, shouldn\'t it?

if (func1() || func2()          


        

Answer 1

You're using the shortcut-operators || and &&. These operators don't execute the rest of the expression, if the result is already defined. For || that means if the first expression is true and for && if the first expression is false.

If you want to execute all parts of the expression use | and & instead, that is not shortcut.