split out file name from path in postgres

Question

I have a field that contains windows file paths, like so:

\\\\fs1\\foo\\bar\\snafu.txt
c:\\this\\is\\why\\i\\drink\\snafu.txt
\\\\fs2\\bippity\\baz.zip
\\\\f         


        

Answer 1

select regexp_replace(path_field, '.+/', '') from files_table;