split out file name from path in postgres

Question

I have a field that contains windows file paths, like so:

\\\\fs1\\foo\\bar\\snafu.txt
c:\\this\\is\\why\\i\\drink\\snafu.txt
\\\\fs2\\bippity\\baz.zip
\\\\f         


        

Answer 1

CREATE OR REPLACE FUNCTION basename(text) RETURNS text
    AS $basename$
declare
    FILE_PATH alias for $1;
    ret         text;
begin
    ret := regexp_replace(FILE_PATH,'^.+[/\\]', '');
    return ret;
end;
$basename$ LANGUAGE plpgsql;