How to sort the name along with age in java

Question

I am new to Java 8. I just want to sort by the name. But the condition is: if there are duplicate names then it should be sorted according to age.

For example my inp

Answer 1

You need to compare for names first. If the names are the same, then and only then the result depends on comparing the age

public static void main(String[] args) {
    List persons = new ArrayList<>();
    persons.add(new Person("tarun", 28));
    persons.add(new Person("arun", 29));
    persons.add(new Person("varun", 12));
    persons.add(new Person("arun", 22));

    Collections.sort(persons, new Comparator() {

        public int compare(Person t, Person t1) {
            int comp = t.getFname().compareTo(t1.getFname());
            if (comp != 0) {    // names are different
                return comp;
            }
            return t.getAge() - t1.getAge();
        }
    });
    System.out.println(persons);

}}

if you want to change from ascending to descending, just change the sign. e.g.

 return -comp;

or swap the person

name

 int comp = t1.getFname().compareTo(t.getFname());

age

 return t1.getAge() - t.getAge();