What is the compiler seeing with this macro? [closed]

Answer 1

You can test it yourself using the -E (*) flag (with gcc/g++):

test.cpp

#define STRINGIFY(A) #A

int main(int argc, const char *argv[])
{
    STRINGIFY(hello);
    return 0;
}

Output of g++ test.cpp -E

# 1 "test.cpp"
# 1 ""
# 1 "test.cpp"


int main(int argc, const char *argv[])
{
    "hello";
    return 0;
}

_{(*): If you use the -E option, nothing is done except preprocessing. - GCC Options Controlling the Preprocessor}