Why MSVC generates warning C4127 when constant is used in “while” - C

Question

For code,

while(1)
{
   /* ..... */
}

MSVC generates the following warning.

warning C4127: conditional expression is const         


        

Answer 1

Constant conditionals are often enough simply bugs. Consider this:

unsigned k; 
...
while (k>=0) 
{
 ...
}

The condition k>=0 would make sense if k was a signed int, but not for unsigned. A careless developer forgets that k was declared unsigned and he/she would use it as if it was usable as a negative number. The compiler tries to be helpful and warn you about this and while(1) falls for the compiler into the same problem class. for(;;) is preferable because it unambiguously means `loop forever