Well, this is kind of hacky:
function b2n(boo) { return boo ? 1 : 0; } if(b2n(opt1) + b2n(opt2) + b2n(opt3) !== 1) { throw new Error(\"Exactly one o
You can do this :
if ( !!opt1 + !!opt2 + !!opt3 !== 1 ) {
It works because
!!
true
if(value)
1
0
false