Regular Expression for Percentage of marks

Question

I am trying to create a regex that matches percentage for marks

For example if we consider few percentages

1)100%
2)56.78%
3)56 78.90%
4)34.6789%
         


        

Answer 1

^((100)|(\d{1,2}(.\d*)?))%$

Check this regular expression here: https://regex101.com/r/Ou3mJI/2

You can use this regular expression. It is valid for:

1. 0 to 100 inclusive
2. With and without decimal places

Below are valid values:

100% is valid
99.802% is valid
98.7% is valid
57% is valid
0% is valid

This regular expression invalidates below values:

1. Negative numbers
2. Number > 100
3. Number with spaces

Invalid value examples:

-1%
99.989%
101%
56 78.90%

Hope this will help!