Regular Expression for Percentage of marks

Question

I am trying to create a regex that matches percentage for marks

For example if we consider few percentages

1)100%
2)56.78%
3)56 78.90%
4)34.6789%
         


        

Answer 1

\\d+(?:\\.\\d+)?%

This should do it for you.

For more stringent test use,

\b(?

See demo.

https://regex101.com/r/zsNIrG/2