Why is this considered an extended initializer list?

Question

#include 

struct foo {
    int i;
    int j;
    int k;
};

int main() {
    std::vector v(1);
    v[0] = {0, 0, 0};
    return 0;
}
         


        

Answer 1

Brace-initialization for aggregates is only valid during declaration-initialization:

Foo a = { 1, 2, 3 };

It is not a way to generate temporaries midway: some_function(true, {1,2,3}, 'c').

C++11 adds uniform initialization in which you can indeed write f(Foo{1,2,3});.