BigInteger or not BigInteger?

Question

In Java, most of the primitive types are signed (one bit is used to represent the +/-), and therefore when I exceed the limits of the type, I can get unexpected results, lik

Answer 1

No, there is not a better solution. If you are working with values that cannot fit into a long or a double then you will need to use a reference type like BigInteger, and Java does not support operator overloading.

Technically, I suppose you could have some mapping between signed and unsigned values, but if your goal is clean and simple code then this is not at all the way to go.