Why is the output of inv() and pinv() not equal in Matlab and Octave?

前端 未结 3 894
死守一世寂寞
死守一世寂寞 2021-01-17 11:33

I have noticed that if A is a NxN matrix and it has the inverse matrix. But what the inv() and pinv() function output is different. - My environment is Win7x64 SP1, Matlab

3条回答
  •  感动是毒
    2021-01-17 12:10

    This question is quite old, but I'll answer it anyway because it appears almost on top in some google searches.

    I'll use for my example the magic(N) function which returns an N-by-N magic square.

    I'll create a 3x3 magic square M3, take the pseudoinverse PI_M3 and multiply them:

       prompt_$ M3 = magic(3) , PI_M3 = pinv(M3) , M3 * PI_M3
      M3 =
    
        8   1   6
        3   5   7
        4   9   2
    
      PI_M3 =
    
         0.147222  -0.144444   0.063889
        -0.061111   0.022222   0.105556
        -0.019444   0.188889  -0.102778
    
      ans =
    
         1.0000e+00  -1.2212e-14   6.3283e-15
         5.5511e-17   1.0000e+00  -2.2204e-16
        -5.9952e-15   1.2268e-14   1.0000e+00
    

    As you can see the answer is the identity matrix save for some rounding errors. I'll repeat the operation with a 4x4 magic square:

       prompt_$ M4 = magic(4) , PI_M4 = pinv(M4) , M4 * PI_M4
     
      M4 =
    
         16    2    3   13
          5   11   10    8
          9    7    6   12
          4   14   15    1
    
      PI_M4 =
    
         0.1011029  -0.0738971  -0.0613971   0.0636029
        -0.0363971   0.0386029   0.0261029   0.0011029
         0.0136029  -0.0113971  -0.0238971   0.0511029
        -0.0488971   0.0761029   0.0886029  -0.0863971
    
      ans =
    
         0.950000  -0.150000   0.150000   0.050000
        -0.150000   0.550000   0.450000   0.150000
         0.150000   0.450000   0.550000  -0.150000
         0.050000   0.150000  -0.150000   0.950000
    

    The result is not the identity matrix, it means that the 4x4 magic square does not have an inverse. I can verify this by trying one of the rules of the Moore-Penrose pseudoinverse:

       prompt_$ M4 * PI_M4 * M4
      
    ans =
    
       16.00000    2.00000    3.00000   13.00000
        5.00000   11.00000   10.00000    8.00000
        9.00000    7.00000    6.00000   12.00000
        4.00000   14.00000   15.00000    1.00000
    

    The rule A*B*A = A is satisfied. This shows that pinv returns the inverse matrix when it is available and the pseudoinverse when the inverse is not available. This is the reason why in some situations you get a small difference, just some rounding errors, and in other situations you get a bigger difference. To show it I'll get the inverse of both magic quadrants and subtract them from the pseudoinverse:

       prompt_$ I_M3 = inv(M3) , I_M4 = inv(M4) , DIFF_M3 = PI_M3 - I_M3, DIFF_M4 = PI_M4 - I_M4
      I_M3 =
    
         0.147222  -0.144444   0.063889
        -0.061111   0.022222   0.105556
        -0.019444   0.188889  -0.102778
    
      warning: inverse: matrix singular to machine precision, rcond = 1.30614e-17
      I_M4 =
    
         9.3825e+13   2.8147e+14  -2.8147e+14  -9.3825e+13
         2.8147e+14   8.4442e+14  -8.4442e+14  -2.8147e+14
        -2.8147e+14  -8.4442e+14   8.4442e+14   2.8147e+14
        -9.3825e+13  -2.8147e+14   2.8147e+14   9.3825e+13
    
      DIFF_M3 =
    
         4.7184e-16  -1.0270e-15   5.5511e-16
        -9.9226e-16   2.0470e-15  -1.0825e-15
         5.2042e-16  -1.0270e-15   4.9960e-16
    
      DIFF_M4 =
    
        -9.3825e+13  -2.8147e+14   2.8147e+14   9.3825e+13
        -2.8147e+14  -8.4442e+14   8.4442e+14   2.8147e+14
         2.8147e+14   8.4442e+14  -8.4442e+14  -2.8147e+14
         9.3825e+13   2.8147e+14  -2.8147e+14  -9.3825e+13
    

提交回复
热议问题