How does std::cout print negative zero in a ones-complement system?

Question

On a ones-complement platform, what would the following code print?

#include 

int main() {
    int i = 1, j = -1;

    std::cout << i+         


        

Answer 1

Looking through the glibc source code, I found these lines in vfprintf.c:

532       is_negative = signed_number < 0;                    \
533       number.word = is_negative ? (- signed_number) : signed_number;      \
534                                           \
535       goto LABEL (number);                            \
...
683       if (is_negative)                            \
684         outchar (L_('-'));                            \

So it would appear that the condition is signed_number < 0, which would return false for a -0.

as @Ysc mentioned, nothing in the documentation gives any specification to printing -0, so a different implementation of libc (on a ones-compliment) platform may yield a different result.