Since you already know how to find the minimum value, you simply feed that value to the index() function to get the index of this value in the list. I.e,
n = [20, 15, 27, 30]
n.index(min(n))
yields
1
This will return the index of the minimum value in the list. Note that if there are several minima it will return the first.
min(): With a single argument iterable, return the smallest item of a non-empty iterable (such as a string, tuple or list). With more than one argument, return the smallest of the arguments.
list.index(x):
Return the index in the list of the first item whose value is x. It is
an error if there is no such item.
