Why does the error “expected to be a reference, value given” appear?

Question

It fires out when I try to call function with argument by reference

function test(&$a) ...

through

call_user_func(\'tes         


        

Answer 1

You need to set the variable equal to the result of the function, like so...

$b = call_user_func('test', $b);

and the function should be written as follows...

function test($a) {
    ...
    return $a
}

The other pass by reference work-a-rounds are deprecated.