The Next Palindrome number

Question

I am beginner in programming, So can you please tell me what\'s wrong with my code?

I want to print next palindrome number if the number entered by the user (n) is n

Answer 1

def nearest_palindrome(number):
    n = len(str(number))//2
    if(len(str(number)) % 2 == 0):
        #number like 1221
        number_1 = int((str(number))[:n]) #12
        number_2 = int((str(number))[n:]) #21
        if(number_1 < number_2):
            number_1 += 1
            number_2 = int(str(number_1)[::-1])
        else:
            number_2 = int(str(number_1)[::-1])
        # if last half part is zero then just reverse the first number
        if number_2 == 0:
            number_2 = str(number_1)[::-1]
        #combining the both parts
        ans = int(str(number_1) + str(number_2))
        return ans
    else:
        #numer like 12510   n=2
        nu = int((str(number))[:n+1]) #add in this number
        number_1 = int((str(number))[:n])  # 12
        number_2 = int((str(number))[n+1:])  # 21
        if (number_1 < number_2):
            nu += 1
            number_2 = int((str(nu))[::-1][1:])
        else:
            number_2 = int((str(nu))[::-1][1:])
        #if last half part is zero then just reverse the first number
        if number_2 == 0:
            number_2 = str(nu)[::-1]
            number_2 = number_2[1:]
        #combinning both parts
        ans = int(str(nu) + str(number_2))
        return ans
number=12331
print(nearest_palindrome(number))