SQL Server 2008 R2: Delete duplicate rows from tables containing in view

Question

--Creating Table dup1

CREATE TABLE dup1
(
    cola VARCHAR(10),
    colb VARCHAR(10)
);

--Insertion of records

INSERT INTO          


        

Answer 1

Create a temp table with the rows need to be deleted from CTE and delete those from both the tables.

Query

CREATE TABLE dup1
(
    cola VARCHAR(10),
    colb VARCHAR(10)
);

INSERT INTO dup1 VALUES('1','2');
INSERT INTO dup1 VALUES('1','2');
INSERT INTO dup1 VALUES('1','3');
INSERT INTO dup1 VALUES('1','4');
INSERT INTO dup1 VALUES('1','5');

CREATE TABLE dup2
(
    cola VARCHAR(10),
    colb VARCHAR(10)
);

INSERT INTO dup2 VALUES('1','2');
INSERT INTO dup2 VALUES('1','2');
INSERT INTO dup2 VALUES('2','3');
INSERT INTO dup2 VALUES('2','4');
INSERT INTO dup2 VALUES('1','5');

CREATE VIEW V_Dup as
SELECT * FROM dup1 UNION ALL
SELECT * FROM dup2;

;with cte as 
(
    select rn=row_number() over
    (
        partition by cola,colb
        order by cola,colb
    ),*
    from V_Dup
)
select * into #temp
from cte 
where rn>1;

delete t1 from dup1 t1
inner join  #temp t2
on t1.cola = t2.cola
and t1.colb = t2.colb;

delete t1 from dup2 t1
inner join  #temp t2
on t1.cola = t2.cola
and t1.colb = t2.colb;

drop table #temp;