Explaining post-increment in C# [duplicate]

Answer 1

As the name says, post-increment increments after the value has been used

y = x++;

According to the C# Language Specification this is equivalent to

temp = x;
x = x + 1;
y = temp;

Applied to your original problem it means that j remains the same after these operations.

temp = j;
j = j + 1;
j = temp;

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You can also use pre-increment, which does the opposite

x = x + 1;
y = x;

or

y = ++x;

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See Postfix increment and decrement operators on MSDN