Multidimensional array fill

前端 未结 2 733
逝去的感伤
逝去的感伤 2021-01-17 01:12

I\'m trying to fill an area in a multidimensional array and not sure on the approach.

For example I have the following array:

var map = [
    [0, 0,          


        
2条回答
  •  情书的邮戳
    2021-01-17 02:04

    This is an alternative implementation (queue-based) roughly translated, no optimisations performed. There are also others.

    Javascript

    var map = [
        [0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 2, 2, 2, 2, 2, 2, 0, 0],
        [0, 2, 0, 0, 0, 0, 2, 0, 0],
        [0, 2, 0, 2, 0, 0, 2, 0, 0],
        [0, 2, 0, 0, 2, 0, 2, 0, 0],
        [0, 0, 2, 0, 0, 0, 2, 0, 0],
        [0, 0, 0, 2, 2, 2, 2, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0]
    ];
    
    /*
     1. Set Q to the empty queue.
     2. If the color of node is not equal to target-color, return.
     3. Add node to Q.
     4. For each element N of Q:
     5.     If the color of N is equal to target-color:
     6.         Set w and e equal to N.
     7.         Move w to the west until the color of the node to the west of w no longer matches target-color.
     8.         Move e to the east until the color of the node to the east of e no longer matches target-color.
     9.         For each node n between w and e:
    10.             Set the color of n to replacement-color.
    11.             If the color of the node to the north of n is target-color, add that node to Q.
    12.             If the color of the node to the south of n is target-color, add that node to Q.
    13. Continue looping until Q is exhausted.
    14. Return.
    */
    function floodFill(data, node, targetValue, replacementValue) {
        var Q;
    
        if (data[node[0]][node[1]] === targetValue) {
            Q = [node];
            while (Q.length) {
                var N = Q.shift(),
                    value,
                    index,
                    n,
                    e,
                    s,
                    w;
    
                if (data.hasOwnProperty([N[0]]) && data[N[0]][N[1]] === targetValue) {
                    w = e = N[0];
                    do {
                        w -= 1;
                    } while (data.hasOwnProperty(w) && data[w][N[1]] === targetValue);
    
                    do {
                        e += 1;
                    } while (data.hasOwnProperty(e) && data[e][N[1]] === targetValue);
    
                    n = N[1] - 1;
                    s = N[1] + 1;
                    for (index = w + 1; index < e; index += 1) {
                        data[index][N[1]] = replacementValue;
                        if (data[index].hasOwnProperty(n) && data[index][n] === targetValue) {
                            Q.push([index, n]);
                        }
    
                        if (data[index].hasOwnProperty(s) && data[index][s] === targetValue) {
                            Q.push([index, s]);
                        }
                    }
                }
            }
        }
    }
    
    floodFill(map, [2, 2], 0, 1);
    map.forEach(function (m) {
        console.log(JSON.stringify(m));
    });
    

    Output

    [0,0,0,0,0,0,0,0,0]
    [0,2,2,2,2,2,2,0,0] 
    [0,2,1,1,1,1,2,0,0]
    [0,2,1,2,1,1,2,0,0] 
    [0,2,1,1,2,1,2,0,0] 
    [0,0,2,1,1,1,2,0,0] 
    [0,0,0,2,2,2,2,0,0]
    [0,0,0,0,0,0,0,0,0] 
    

    On jsFiddle

提交回复
热议问题