submitting form and variables together through jquery

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醉酒成梦
醉酒成梦 2021-01-17 01:30

I\'m using 2 types of submit.

There is $.post

$.post(\'servers_side.php\', { var1: var1, var2:var2},
function(result) 
{
some code...
});

2条回答
  •  予麋鹿
    予麋鹿 (楼主)
    2021-01-17 02:08

    Update

    And here is how you can submit:

    var Vars = {var1: var1, var2:var2};
    var varsData = $.param(Vars);
    
    // form data
    var formData = $('#formID').serialize();
    
    var data = varsData + '&' + formData;
    
    $.ajax({
      type: 'POST',
      url: 'servers_side.php',
      data: data,
      success: function(res){ alert (res) }
    })
    

    You can use jQuery.param() to convert an array or an object into url-friendly name-value paris. You may also need to use jQuery.serialize() to convert form data into name-value paris. Here is how you can go about:

    var Vars = {var1: var1, var2:var2};
    var varsData = $.param(Vars);
    
    // form data
    var formData = $('#formID').serialize();
    
    var data = varsData + '&' + formData;
    

    Now data contains all data of your custom vars and form elements you can send in ajax request.

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