dynamic prepared insert statement

Question

Let me preface that I just started learning prepared statements so much of this might just be to much to grasp, but I want to try.

I am trying to make a dynamic crea

Answer 1

I accidently found your old post as I was trying myself to find a solution to the exact same problem. My code seems a bit more advantagous as there is only one loop included. Therefore I will add it as a possible improvement to this post:

    $sqlquery = $this->MySQLiObj->prepare($dummy);

    $paramQuery = array();
    $paramQuery[0] = '';

    $n = count($valueArray);
    for($i = 0; $i < $n; $i++) {
        $checkedDataType = $this->returnDataType($valueArray[$i]);
        if($checkedkDataType==false) {
            return false;
        }
        $paramQuery[0] .= $checkedDataType;
        /* with call_user_func_array, array params must be passed by reference -> & */
    $paramQuery[] = &$valueArray[$i];
    }

    /*In array(): sqlquery(object)->bind_param(method)*/
    call_user_func_array(array($sqlquery, 'bind_param'), $paramQuery);
    $sqlquery->execute();
    /*Can be used identical to $result = $mysqli->query()*/
    $result = $this->MySQLiObj->get_result();
    $sqlquery->close();

Utilizing the function returnDataType() with a switch statement, which might be faster if there is a preference for a certain data type.

    private function returnDataType($input) {
    switch(gettype($input)) {
        case string: return 's';
        case double: return 'd';
        case integer: return 'i';
        default: $this->LOG->doLog("Unknown datatype during database access."); return 's';
    }
}