Displaying floating point variable as a hex integer screws up neighbouring integer

Question

I have this simple program

#include 
int main(void)
{
 unsigned int a = 0x120;
 float b = 1.2;
 printf(\"%X %X\\n\", b, a);
 return 0;
}
         


        

Answer 1

If you want to see the bits of a stored float, use a union:

 float b = 1.2;
 union {
      float  f;
      int    i;
 } u;
 u.f = b;

 printf ("%x\n", u.i);

results (32-bit x86):

3f99999a