Adding pointers to vector in loop

Question

I am slightly confused about the following code

void foo() {

  std::list list;

  for (int i = 0; i < 3; i ++) {
    A a = A(i);
    list.push_         


        

Answer 1

You have a list of dangling pointers.

 for (int i = 0; i < 3; i ++) {
    A a = A(i);
    list(&a);
  }

In each iteration, this loop creates an object of type A, which is immediately destroyed when the iteration completes. So the contents of the list are undefined. You would need something like this:

 for (int i = 0; i < 3; i ++) {
    A* a = new A(i);
    list(a);
  }

...but don't forget to delete them all in another loop when you're done with the list.