greediness in sed

Question

I want

ereg ($rat, $dog, $cat)

to become

preg_match (\'#\'.$rat.\'#\', $dog, $cat)

To achieve this, I did

Answer 1

Just exclude ','...

echo 'ereg ($rat, $dog, $cat)' | sed "s/ereg\(.*\)(\([^,]*\),/preg_match\1('#'.\2.'#',/g"