Java - “String index out of range” exception

Question

I wrote this little function just for practice, but an exception (\"String index out of range: 29\") is thrown and I don\'t know why...

(I know this isn\'t the best

Answer 1

Looks like you are a C/C++ programmer coming to java ;)

Once you have gone out of range with .charAt (), it doesn't reach null, it reaches a StringIndexOutOfBoundsException. So in this case, you will need a for loop that goes from 0 to y.length()-1.