Pattern decoding

Question

I need a little help in the following. I have this kind of datafile:

0 0    # <--- Group 1 -- 1 house (0) and 1 room (0)

0 0    # <--- Group 2 -- 2 ho         


        

Answer 1

I don't know what would be your expected output, however I have converted/decoded your number pattern to a meaningful group/house/rooms format. any further "query" could be done on this content.

see below:

kent$  cat file
0 0

0 0
0 1
0 2
1 0
1 1

0 0
0 1
0 2

0 0
1 0
2 0
3 0

0 0

0 0

awk:

kent$  awk 'BEGIN{RS=""} 
        { print "\ngroup "++g; 
        delete a;
        for(i=1;i<=NF;i++) if(i%2) a[$i]++;
        for(x in a) printf "House#: %s , Room(s): %s \n", x, a[x]; }' file

we get output:

group 1
House#: 0 , Room(s): 1 

group 2
House#: 0 , Room(s): 3 
House#: 1 , Room(s): 2 

group 3
House#: 0 , Room(s): 3 

group 4
House#: 0 , Room(s): 1 
House#: 1 , Room(s): 1 
House#: 2 , Room(s): 1 
House#: 3 , Room(s): 1 

group 5
House#: 0 , Room(s): 1 

group 6
House#: 0 , Room(s): 1 

note that the generated format could be changed to fit your "filter" or "query"

UPDATE

OP's comment:

I need to know, the number of the group(s) which have/has for example 1 house with one room. The output would be in the above case: 1, 5 ,6

as I said, based on your query criteria, we could adjust the awk output for next step. now I change the awk abovet to:

awk 'BEGIN{RS=""} 
        {print "";  gid=++g; 
        delete a;
        for(i=1;i<=NF;i++) if(i%2) a[$i]++;
        for(x in a) printf "%s %s %s\n", gid,x, a[x]; }' file

this will output:

1 0 1

2 0 3
2 1 2

3 0 3

4 0 1
4 1 1
4 2 1
4 3 1

5 0 1

6 0 1

the format is groupIdx houseIdx numberOfRooms and there is a blank line between groups. we save the text above to a file named decoded.txt

so your query could be done on this text:

kent$  awk 'BEGIN{RS="\n\n"}{if (NF==3 && $3==1)print $1}' decoded.txt
1
5
6

the last awk line above means, print the group number, if room number ($3) = 1 and there is only one line in the group block.