why Java throws a NumberFormatException

Question

I got an exception while parsing a string to byte

String Str =\"9B7D2C34A366BF890C730641E6CECF6F\";

String [] st=Str.split(\"(?<=\\\\G.{2})\");

byte[]by         


        

Answer 1

Assuming you want to parse the string as hexadecimal, try this:

bytes[i] = Byte.parseByte(st[i], 16);

The default radix is 10, and obviously B is not a base-10-digit.