Paypal OAuth login example doesn't work as expected

Question

I\'m following this interactive login example from Paypal\'s site.

  public ActionResult PaypalResponse(string scope, string code)
    {
        Dictionary&l         


        

Answer 1

I had the exact same problem, and solved it changing call method

string postcontents = string.Format("client_id={0}&client_secret={1}&grant_type=authorization_code&redirect_uri={2}&code={3}"
                                      , System.Web.HttpUtility.UrlEncode(clientId)
                                      , System.Web.HttpUtility.UrlEncode(secret)
                                      , System.Web.HttpUtility.UrlEncode(url)
                                      , System.Web.HttpUtility.UrlEncode(code));


        HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create("https://api.sandbox.paypal.com/v1/identity/openidconnect/tokenservice");
        request.Credentials = new NetworkCredential(clientId, secret);
        request.Method = "POST";
        byte[] postcontentsArray = System.Text.Encoding.UTF8.GetBytes(postcontents);
        request.ContentType = "application/x-www-form-urlencoded";
        request.ContentLength = postcontentsArray.Length;
        //OAuth.
        using (Stream requestStream = request.GetRequestStream())
        {
            requestStream.Write(postcontentsArray, 0, postcontentsArray.Length);
            requestStream.Close();
            WebResponse response = request.GetResponse();
            using (Stream responseStream = response.GetResponseStream())
            using (StreamReader reader = new StreamReader(responseStream))
            {
                string responseFromServer = reader.ReadToEnd();
                reader.Close();
                responseStream.Close();
                response.Close();
                // return SerializeToken(responseFromServer);
                dynamic dynObj = JsonConvert.DeserializeObject(responseFromServer);
                string token = dynObj["access_token"];
                //token = ser.Deserialize(responseFromServer);
            }
        }

Hope it helps