How I return the size of the pointer that I have allocate with malloc?

Question

See this example!

int main( int argc, char ** argv )
{
    int *ptr = malloc(100 * sizeof (int));

    printf(\"sizeof(array) is %d bytes\\n\", sizeof(ptr)         


        

Answer 1

Nothing is wrong. You are asking for, and getting, the size of the pointer on your platform.

It is not in general possible to get the size of the memory block that a pointer points at, you must remember it yourself if you need it later.