PHP Pass by reference error after using same var

Question

Take a look to this code, and help me to understand the result

$x = array(\'hello\', \'beautiful\', \'world\');
$y = array(\'bye bye\',\'world\', \'harsh\');         


        

Answer 1

// ...
$v = "DONT CHANGE!";
unset($v);
// ...

because $v is still a reference, which later takes the last item in the last foreach loop.

EDIT: See the reference where it reads (in a code block)

unset($value); // break the reference with the last element