How to create new closure cell objects?

Question

I need to monkey-patch my library to replace an instance of a symbol, and it\'s getting referenced by some function closures. I need to copy those functions (since I also ne

Answer 1

in lambda:

def make_cell(value):
    fn = (lambda x: lambda: x)(value)
    return fn.__closure__[0]

got anwer from https://github.com/nedbat/byterun/blob/master/byterun/pyobj.py#L12