ES6 .filter within a .filter

Question

So I have data like the following:

[
     {
      \"id\": 0,
      \"title\": \"happy dayys\",
      \"owner\": {\"id\": \"1\", \"username\": \"dillonraphael         


        

Answer 1

To use filter() you need something that will return true or false -- i.e. a Boolean. That should be the first place you start. So given an object like

{
 "id": 0,
 "title": "happy dayys",
 "owner": {"id": "1", "username": "dillonraphael"},
 "tags": [{"value": "Art", "label": "Art"}],
 "items": []
},

if you want to decide whether or not that should be used, you might try Array.some() on the tags array. This will return a boolean.

let tags = [{"value": "Art", "label": "Art"}]

console.log(tags.some(tag => tag.value = "Art")) // true

With that in hand, you can now use filter() and some() together. some() will return true or false for each item in the array and that will determine whether it's filtered or not:

let arr =  [{"id": 0,"title": "happy dayys","owner": {"id": "1", "username": "dillonraphael"},"tags": [{"value": "Art", "label": "Art"}],"items": []},{"id": 1,"title": "happy dayys","owner": {"id": "1", "username": "dillonraphael"},"tags": [{"value": "Architecture", "label": "Architecture"}],"items": []},]

console.log(arr.filter(obj => obj.tags.some(o => o.value == 'Art') ))