how to select record whose matching percentage is higher than other using like operator in sql server?

Question

I have set of records which I need to search using criteria. But criteria is returning me multiple rows.

So I need top 2 records which are having maximum percentage

Answer 1

Given solutions not worked for me,

So I created my own logic:

SELECT TOP 2 FirstName, LastName, CountryName, StateName 
FROM Employee
WHERE
    statename like '%Gujarat%' AND countryname like '%India%'
ORDER BY
    LEN(StateName + CountryName) - LEN(REPLACE(StateName, 'Gujarat', '') + REPLACE(CountryName, 'India', '')) DESC

Hope this help...