how to select record whose matching percentage is higher than other using like operator in sql server?

Question

I have set of records which I need to search using criteria. But criteria is returning me multiple rows.

So I need top 2 records which are having maximum percentage

Answer 1

As far as I understand you need something like Fuzzy String Matching using Levenshtein Distance Algorithm. Hope the link will be helpful.

You need to calculate distance between CountryName and search pattern. It's not exactly the "percentage", but it can measure the relevance.

Maybe this solves your problem?

SELECT TOP 2 FirstName, LastName, CountryName, StateName 
FROM Employee
WHERE
    statename like '%Gujarat%' AND countryname like '%India%'
ORDER BY
    dbo.edit_distance(statename, 'Gujarat') + dbo.edit_distance(CountryName, 'India') DESC