Printing a pointers value

Question

#include 

int main(void)
{
   int x = 99;
   int *pt1;

   pt1 = &x;

   printf(\"Value at p1: %d\\n\", *pt1);
   printf(\"Address of p1 (with %%         


        

Answer 1

%d displays an integer - there is no need for the size of a pointer to equal the size of an integer.