why didn't the positive terms get displayed in this asbolute program

Question

Let\'s start with this demo

#include 
using namespace std;

template 
void abs(T number)
{
   if (number < 0)
        numbe         


        

Answer 1

There is an abs function built-in to the standard library:

int abs ( int n );
long abs ( long n );

The compiler is going to use these versions in preference to your templated function since non-templated functions are more specific than templated functions, and thus take precedence in function overload resolution.

I recommend that you rename your abs function to something else to fix this.

As a side note, this might be questionable behavior on the part of your standard library implementation. It appears that #include is pulling in a non-std-namespaced declaration of abs and it probably shouldn't be doing that. If you switch to C-style printfs then your program works fine without having to rename anything (at least on my platform, that is).

#include 

template 
void abs(T number)
{
   if (number < 0)
        number = -number;
   printf("The absolute value of the number is %g\n", (double) number);
   return;
}

int main()
{
   int num1 = 1;
   int num2 = 2;
   double num3 = -2.1333;
   float num4 = -4.23f;

   abs(num1);
   abs(num2);
   abs(num3);
   abs(num4);

   return 0;
}

I don't recommend that as a solution, just as a curiosity.