Retrieve method content as an `Expr`ession

Question

I have a function f defined as follows.

f(x, y) = 3x^2 + x*y - 2y + 1

How can I retrieve the following quote bloc

Answer 1

First, retrieve the method using methods(f).

julia> methods(f)
# 1 method for generic function "f":
f(x, y) at REPL[1]:1

julia> methods(f).ms
1-element Array{Method,1}:
 f(x, y) at REPL[1]:1

julia> method = methods(f).ms[1]
f(x, y) at REPL[1]:1

From here, retrieving the Expression is straightforward; simply use the lambda_template attribute of the method.

julia> method.lambda_template
LambdaInfo template for f(x, y) at REPL[1]:1
:(begin 
        nothing
        return ((3 * x ^ 2 + x * y) - 2 * y) + 1
    end)

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Edit: This does not work in Julia v0.6+!