Integer division without using the / or * operator

Question

I am going through an algorithms and datastructures textbook and came accross this question:

1-28. Write a function to perform integer division withou

Answer 1

This is not the fastest solution, but I think it's readable enough and works:

def weird_div(dividend, divisor):
    if divisor == 0:
        return None

    dend = abs(dividend)
    dsor = abs(divisor)
    result = 0
    
    # This is the core algorithm, the rest is just for ensuring it works with negatives and 0
    while dend >= dsor:
        dend -= dsor
        result += 1
    
    # Let's handle negative numbers too
    if (dividend < 0 and divisor > 0) or (dividend > 0 and divisor < 0):
        return -result
    else:
        return result

# Let's test it:
print("49 divided by 7 is {}".format(weird_div(49,7)))
print("100 divided by 7 is {} (Discards the remainder) ".format(weird_div(100,7)))
print("-49 divided by 7 is {}".format(weird_div(-49,7)))     
print("49 divided by -7 is {}".format(weird_div(49,-7)))   
print("-49 divided by -7 is {}".format(weird_div(-49,-7)))   
print("0 divided by 7 is {}".format(weird_div(0,7)))         
print("49 divided by 0 is {}".format(weird_div(49,0)))

It prints the following results:

49 divided by 7 is 7
100 divided by 7 is 14 (Discards the remainder) 
-49 divided by 7 is -7
49 divided by -7 is -7
-49 divided by -7 is 7
0 divided by 7 is 0
49 divided by 0 is None