How should C bitflag enumerations be translated into C++?

Question

C++ is mostly a superset of C, but not always. In particular, while enumeration values in both C and C++ implicitly convert into int, the reverse isn\'t true: only in C do i

Answer 1

It sounds like an ideal application for a cast - it's up to you to tell the compiler that yes, you DO mean to instantiate a Foo with a random integer.

Of course, technically speaking, Foo_First | Foo_Second isn't a valid value for a Foo.