Emit DbContext.OnModelCreating on every context creation

Question

I use entity framework code first to work with my database. I have several tables with different names but same structure, and this tables dynamically appears in database. H

Answer 1

There is a built-in feature which may address your issue : `IDbModelCacheKey ; the implementation of which is to be registered in your configuration. The point is to generate a different key for your different contexts.

I would go for something like :

First, the configuration

public class EntityFrameworkConfiguration: DbConfiguration
{
    public EntityFrameworkConfiguration()
    {
        this.SetModelCacheKey(ctx => new EntityModelCacheKey((ctx.GetType().FullName + ctx.Database.Connection.ConnectionString).GetHashCode()));
    }
}

Then the implementation of the IDbModelCacheKey

public class EntityModelCacheKey : IDbModelCacheKey
{
    private readonly int _hashCode;

    public EntityModelCacheKey(int hashCode)
    {
        _hashCode = hashCode;
    }

    public override bool Equals(object other)
    {
        if (other == null) return false;
        return other.GetHashCode() == _hashCode;
    }

    public override int GetHashCode()
    {
        return _hashCode;
    }
}

Finally, your DataContext

public class DataContext : DbContext
{

  string setElementsTableId; 

  // use the setElementsTableId as extended property of the 
  // connection string to generate a custom key
  public DataContext(string setElementsTableId)
        : base(ConfigurationManager.ConnectionStrings["RepositoryConnectionString"] 
 + "; Extended Properties=\"setElementsTableId=" + setElementsTableId + "\"")
  {
    this.setElementsTableId = setElementsTableId;
  }

  public DbSet SetElements { get; set; } 

  protected override void OnModelCreating(DbModelBuilder modelBuilder)
  {
    if (!string.IsNullOrEmpty(setElementsTableId))
    {
        modelBuilder.Entity().Map(x => x.ToTable(setElementsTableId)); 
    }
  }
}

I hope this will be of some help