Is-there an opposite of the `race` operator in RxJS?

Question

I have two observables and I want listen to the one that emits its first value last, is there an operator for this ? Something like that :

let obs1 = Rx.Obse         


        

Answer 1

I see this possibility, for now, but I'm curious if someone find anything else :

let obs1 = Rx.Observable.timer(500,500).map(i=>`cheetah ${i}`);
let obs2 = Rx.Observable.timer(1000,1000).map(i=>`sloth ${i}`);
let sloth = Rx.Observable.merge(
  obs1.take(1).mapTo(obs1),
  obs2.take(1).mapTo(obs2)
).takeLast(1).mergeAll()

sloth.subscribe(data=>console.log(data))

Edit as pointed out by @user3743222 (very nice nickname :-D ), it would not work for hot observables, but this should be fine :

let obs1 = Rx.Observable.timer(500,500).map(i=>`cheetah ${i}`).publish();
let obs2 = Rx.Observable.timer(1000,1000).map(i=>`sloth ${i}`).publish();
obs1.connect();
obs2.connect();
let sloth = Rx.Observable.merge(
  obs1.take(1).map((val)=>obs1.startWith(val)),
  obs2.take(1).map((val)=>obs2.startWith(val))
).takeLast(1).mergeAll();
    
sloth.subscribe(data=>console.log(data));