How to compare all items in a list with an integer without using for loop

Question

I have a couple of lists which vary in length, and I would like to compare each of their items with an integer, and if any one of the items is above said integer, it breaks

Answer 1

Well, I'd probably do it using the generator expression, but since no one else has suggested this yet, and it doesn't have an (explicit) nested loop:

>>> lol = [[1,2,3],[4,40],[10,20,30]]
>>> 
>>> for l in lol:
...     if max(l) > 30:
...         continue
...     print l
... 
[1, 2, 3]
[10, 20, 30]