What exactly is the ->* operator?

Question

I\'ve never used it before and just stumbled upon it in an article... I thought it would be the equivalent to *x->y but apparently it isn\'t.

Here\'s

Answer 1

It defines a pointer to a member.

In an expression containing the –>* operator, the first operand must be of the type "pointer to the class type" of the type specified in the second operand, or it must be of a type unambiguously derived from that class. MSDN