Cout long double issue

Question

So, I\'m working on a C++ project. I have a var of long double type and assigned it a value like \"1.02\"

Then, I try to use cout to print it and the result is: -0

Answer 1

This is an easier method, but your program worked on my compiler.

#include 
#include 
#include 

using namespace std;

int main(int argc, char** argv)
{

    std::setprecision(10);
    long double var = 1.023563457578;
    cout << var << endl;
    return 0;
}

I hope this helps you see that your compiler might actually have a problem.

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