Datetime to epoch conversion

Question

I have a bash question (when using awk). I\'m extracting every single instance of the first and fifth column in a textfile and piping it to a new file with the following cod

Answer 1

Using GNU awk

Input

$ cat f
Timestamp                 Stream     Status     Seq         Loss Bytes    Delay
17/02/01.10:58:25.212577  stream_0     OK      80281          0  1000     38473
17/02/01.10:58:25.213401  stream_0     OK      80282          0  1000     38472
17/02/01.10:58:25.215560  stream_0     OK      80283          0  1000     38473
17/02/01.10:58:25.216645  stream_0     OK      80284          0  1000     38472

Output

$ awk '
BEGIN{cyear = strftime("%y",systime())}
function epoch(v,       datetime){
    sub(/\./," ",v);
    split(v,datetime,/[/: ]/); 
    datetime[1] = datetime[1] <= cyear ? 2000+datetime[1] : 1900+datetime[1];
    return mktime(datetime[1] " " datetime[2] " " datetime[3] " " datetime[4]" " datetime[5]" " datetime[6])
}
/stream_0/{
    print epoch($1),$5
}' f



1485926905 0
1485926905 0
1485926905 0
1485926905 0

To write to new file just redirect like below

cut -f4 test170201.rawtxt | awk '
BEGIN{cyear = strftime("%y",systime());}
function epoch(v,       datetime){
    sub(/\./," ",v);
    split(v,datetime,/[/: ]/); 
    datetime[1] = datetime[1] <= cyear ? 2000+datetime[1] : 1900+datetime[1];
    return mktime(datetime[1] " " datetime[2] " " datetime[3] " " datetime[4]" " datetime[5]" " datetime[6])
}
/stream_0/{
    print epoch($1),$5
}'  > testLogFile.txt