Simultaneous variable assignment in Go different from individual variable assignment

Question

I was under the impression that despite the differences in syntax, function a and function b below were logically equivalent. However, they are not and I do not understand t

Answer 1

Assignment can be thought of as an "atomic" operation. That is, it's useful to think that all values on the left hand side of the = are "frozen" until all of the operations are finished.

Consider the following program:

package main

import "fmt"

func swap() (int, int) {
    x := 1
    y := 2
    x, y = y, x
    return x, y
}

func main() {
    fmt.Println(swap()) // prints 2 1
}

Without this "freezing" behaviour, you would get 2 for both x and y, which is probably not what you'd expect from the code. It's also probably easier to reason about the semantics of this "freezing" behaviour than if the "cascading" approach were taken.