printing the integral part of a floating point number

Question

I am trying to figure out how to print floating point numbers without using library functions. Printing the decimal part of a floating point number turned out to be quite ea

Answer 1

Like Agent_L's answer, you're suffering from the false result caused by dividing the value by 10. Float, like any binary floating point type, cannot express correctly most rational number in decimal. After division, most of the case the result cannot be fitted into binary, so it'll be rounded. Hence the more you divide, the more error you'll realize.

If the number is not very large, a quick solution would be multiplying it with 10 or a power of 10 depending on how many digits after decimal point you need.

Another way was described here